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how to replace 5th line using bash script !
shyaminayesh
Barred
in Help
i need to replace 5th line of remi.repo file using bash script. i try to do it using sed command and i failed to do it using sed. please help me to correct my errors. this is my remi.repo file's first 7 lines located in /etc/yum.repos.d/ ...
[remi]
name=Les RPM de remi pour Enterprise Linux 6 - $basearch
#baseurl=http://rpms.famillecollet.com/enterprise/6/remi/$basearch/
mirrorlist=http://rpms.famillecollet.com/enterprise/6/remi/mirror
enabled=0
gpgcheck=1
gpgkey=file:///etc/pki/rpm-gpg/RPM-GPG-KEY-remi
now i need to change 5th line enabled=0 to enabled=1 .
this sed command working and echo result with enabled=1 but it not saved in remi.repo file. please help me to do this. thank you so much.
sed -n -e "5s/enabled=0/enabled=1/" remi.repo
Comments
sed -i
sed -i 's/enabled=0/enabled=1/g' remi.repo
^^ that will work assuming you dont have "enabled=0" anywhere else in the file.
@rds100 :
sed -iis working thank you so much ...@AnthonySmith : there is another 4 or 5 enable=0 in my configuration file ... anyway thank you so much for the help
sed -iis working ...sed -i 's/enabled=0/enabled=1/g' remi.repo --> /g = replace every occurrence
sed -i 's/enabled=0/enabled=1/' remi.repo --> no /g = replace the first occurrence