Howdy, Stranger!

It looks like you're new here. If you want to get involved, click one of these buttons!


Shells Virtual Desktop
BMail.ag - Secure Email Service
Server.net
CPLicense.net
VPS Server
Buy VPN
Vultr
VMs for AI
HostDare
ReliableSite White-Label Dedicated Hosting for Resellers
InterServer VPS
BMail.ag - Secure Email Service
Best VPN
High-Performance Bare Metal Server Solutions
Karvl.com
Server Mania Cloud Hosting
DataWagon Hosting
AlphaVPS Hosting
Evoxt.com
Clouvider
VPS Hosting with NVMe
Residential IPs in the US & 4G Mobile Proxies in EU & US with Unlimited Bandwidth
ReliableSite White-Label Dedicated Hosting for Resellers
Rabisu - Hosting Solutions
Shells Virtual Desktop

In this Discussion

New on LowEndTalk? Please Register and read our Community Rules.

All new Registrations are manually reviewed and approved, so a short delay after registration may occur before your account becomes active.

Hiring JavaScript Coder (Simple Task)

KittenKitten Member
edited May 2014 in General

Hi. I am looking to hire someone that is good at JavaScript to complete a small task for me.

Willing to pay $20 via PayPal or BitCoin due to the simplicity of the task.

I currently have a website similar to http://preev.com/ and am having troubles with updating the field values via Javascript.

You can PM me here and I can give you access via FTP to a copy of the files.

Basically I have 3 fields.

Value1
Value2
Value3

I need it so if someone changes value 1, values 2 and 3 automatically recalculate.
If someone changes value 2, then value 1 and 3 automatically recalculate.
If someone changes value 3 then values 1 and 2 automatically recalculate.

My idea was to create 3 functions and use onKeyUp() to call the functions but I could not get that working.

Further details can be discussed via pm

Comments

  • dnomdnom Member

    Sounds simple enough I'll take you up on your offer if you still need help. You may PM me the details.

  • KittenKitten Member

    Hi. @NickM has completed this for me. This thread can be closed

This discussion has been closed.